(5y^2+3)+(6y+4)=

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Solution for (5y^2+3)+(6y+4)= equation:


Simplifying
(5y2 + 3) + (6y + 4) = 0

Reorder the terms:
(3 + 5y2) + (6y + 4) = 0

Remove parenthesis around (3 + 5y2)
3 + 5y2 + (6y + 4) = 0

Reorder the terms:
3 + 5y2 + (4 + 6y) = 0

Remove parenthesis around (4 + 6y)
3 + 5y2 + 4 + 6y = 0

Reorder the terms:
3 + 4 + 6y + 5y2 = 0

Combine like terms: 3 + 4 = 7
7 + 6y + 5y2 = 0

Solving
7 + 6y + 5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
1.4 + 1.2y + y2 = 0

Move the constant term to the right:

Add '-1.4' to each side of the equation.
1.4 + 1.2y + -1.4 + y2 = 0 + -1.4

Reorder the terms:
1.4 + -1.4 + 1.2y + y2 = 0 + -1.4

Combine like terms: 1.4 + -1.4 = 0.0
0.0 + 1.2y + y2 = 0 + -1.4
1.2y + y2 = 0 + -1.4

Combine like terms: 0 + -1.4 = -1.4
1.2y + y2 = -1.4

The y term is 1.2y.  Take half its coefficient (0.6).
Square it (0.36) and add it to both sides.

Add '0.36' to each side of the equation.
1.2y + 0.36 + y2 = -1.4 + 0.36

Reorder the terms:
0.36 + 1.2y + y2 = -1.4 + 0.36

Combine like terms: -1.4 + 0.36 = -1.04
0.36 + 1.2y + y2 = -1.04

Factor a perfect square on the left side:
(y + 0.6)(y + 0.6) = -1.04

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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